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📘 GCSE Foundation Maths Rescue System

Unit 10: Coordinate Geometry

Grade 4/5 Focus · Gradient from points, find equations & parallel lines

y = mx + c Gradient from Points Point Substitution Parallel Lines
AQA 8300 Edexcel 1MA1 OCR J560
🎯 Unit Progress
0 / 6 skills
How to use this lesson
1. Complete the warm-up questions from memory
2. Study the worked examples carefully
3. Try the practice problems: Green → Amber → Red
4. Check your answers and complete the mastery checklist
GCSE Foundation Maths Revision Pathway

A structured 10-unit revision system to help Foundation students build from Grade 3 towards Grade 4/5.

1 Algebra & Sequences
2 Expanding & Factorising
3 Indices & Powers
4 Linear Equations
5 Inequalities
6 Straight-Line Graphs
7 Non-Linear Graphs
8 Real-Life Graphs
9 Graph Applications
📖 Unit 10 — Coordinate Geometry (current)
🔥
Warm-Up: Retrieval Practice
⏱ Before You Start
Answer from memory — no notes!
Q1  Find gradient from (0, 0) to (3, 9)
Q2  Identify y-intercept in:   y = 4x − 7
Q3  Write equation: gradient 2, intercept 5
Q4  🔄 RECALL  Solve: −2x > 8
Q4  Solve:   −2x > 8
Lesson Progress
✓ Warm-up — complete
→ Worked examples & key concepts
· Tiered practice (Green → Amber → Red)
· Mistake Detective & Examiner Lens
· Mastery checklist
💡
The Big Idea: Lines Have Rules

Every straight line can be described by y = mx + c

m = gradient
c = y-intercept

In coordinate geometry, we find m and c from given information: points, gradients, or parallel lines.

Finding Gradient = Rise ÷ Run 0 x y (1, 3) (5, 11) Run = 4 Rise = 8 m = 8 ÷ 4 = 2
Gradient = rise ÷ run = (y₂ − y₁) ÷ (x₂ − x₁)
📖
Core Definitions
Gradient (m)
Change in y ÷ change in x (rise over run)
y-intercept (c)
Value of y when x = 0 (where line crosses y-axis)
Parallel Lines
Lines with the same gradient
Point Substitution
Replacing x and y with coordinates to find c
Midpoint
The point exactly halfway between two coordinates — average the x's, average the y's
✏️
Worked Examples
Worked Example 01Given Gradient and Intercept
Gradient = 3, y-intercept = 4
1
Substitute into y = mx + c: m = 3, c = 4
✓ Answer
y = 3x + 4
Worked Example 02Gradient and Point on y-axis
Gradient = 2, passing through (0, 5)
1
Point where x = 0 gives intercept directly: c = 5
✓ Answer
y = 2x + 5
Worked Example 03Gradient and Non-Zero PointKEY SKILL
Gradient = 4, passing through (2, 3)
1
Start with: y = 4x + c
2
Substitute (2, 3): 3 = 4(2) + c3 = 8 + c
3
Solve: c = 3 − 8 = −5
✓ Answer
y = 4x − 5
Worked Example 04Given Two PointsNEW
Find equation through (1, 3) and (5, 11)
1
Gradient: rise = 11 − 3 = 8, run = 5 − 1 = 4 → m = 8 ÷ 4 = 2
2
Start: y = 2x + c
3
Substitute (1, 3): 3 = 2(1) + cc = 1
✓ Answer
y = 2x + 1
Worked Example 05Parallel Lines
Find equation parallel to y = 3x − 2, through (0, 7)
1
Parallel = same gradientm = 3
2
Point (0, 7) gives c = 7
✓ Answer
y = 3x + 7
💡 Parallel lines: same gradient, different y-intercept.
Parallel Lines = Same Gradient 0 y = 2x + 5 5 y = 2x + 1 1 same gradient (m = 2) different intercepts
Parallel lines never meet — they always have the same gradient but different y-intercepts.
🔍 Upper Foundation Boundary
Perpendicular Lines: gradients multiply to −1. If one gradient is 2, the perpendicular gradient is −½. This appears occasionally on higher Foundation papers.
Worked Example 06Finding the MidpointNEW
Find the midpoint of (2, 3) and (8, 11)
1
Average the x-coordinates: (2 + 8) ÷ 2 = 5
2
Average the y-coordinates: (3 + 11) ÷ 2 = 7
✓ Midpoint
(5, 7)
💡 Midpoint = "average the x's, average the y's". It's the point exactly halfway between.
Midpoint = Average the Coordinates A (2, 3) B (8, 11) M (5, 7) x: (2+8)÷2 = 5    y: (3+11)÷2 = 7
The midpoint M is the average of both coordinates — exactly halfway between A and B.
Process Checklist
📋 Finding the Equation of a Line
🧮
Arithmetic Support
Rise = y₂ − y₁
Run = x₂ − x₁
Substitute carefully
Keep subtraction order consistent
💪
Tiered Practice
🔓 How It Works
Tap any card to reveal the full working and answer.
0 / 14
Problems revealed
Tap problems to reveal working and answers
🟢 Green — Core Skills
🟢 Green · TYPE YOUR ANSWER
Find gradient: (2, 1) to (6, 9)
>
🔍
Mistake Detective
⚠️ These mistakes cost marks
Study each one carefully.
❌ Wrong
Gradient = (x₂ − x₁) ÷ (y₂ − y₁)
Rise and run are reversed!
✅ Correct
m = (y₂ − y₁) ÷ (x₂ − x₁) Rise over run
❌ Wrong
Forgot to substitute point to find c y = 2x + ???
Can’t finish the equation without finding c
✅ Correct
Substitute (x, y) into y = mx + c Then solve for c e.g. 3 = 2(1) + c → c = 1
🎓
Examiner Lens
🎓 To Gain Full Marks
🏆
Mastery Checklist
🏆 Unit 10 Mastery
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Your Grade 3→5 Rescue System
10 units · Algebra, Graphs & Coordinate Geometry
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